Vectors - Class 11 Physics

Complete guide with concepts, formulas, solved examples & practice questions

CBSE, ICSE, IGCSE, IB aligned | Updated for 2025-26

Quick Formula Reference

Magnitude: \(|\vec{a}| = \sqrt{a_x^2 + a_y^2 + a_z^2}\)
Unit Vector: \(\hat{a} = \frac{\vec{a}}{|\vec{a}|}\)
Dot Product: \(\vec{a} \cdot \vec{b} = a_xb_x + a_yb_y + a_zb_z\)
Angle: \(\cos\theta = \frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|}\)
Resultant: \(|\vec{R}| = \sqrt{A^2 + B^2 + 2AB\cos\theta}\)

Core Concepts

Definition: A vector is a mathematical quantity that has both magnitude (size) and direction. Unlike scalars, which only have magnitude, vectors are used to represent physical quantities like displacement, velocity, force, and acceleration.

Vectors are typically represented by an arrow, where:

  • The length of the arrow represents the magnitude
  • The arrowhead indicates the direction

Examples of Vector Quantities:

  • Displacement
  • Velocity
  • Acceleration
  • Force
  • Momentum
  • Electric field
Property Scalar Vector
Has magnitude
Has direction
Examples Mass, Speed, Temperature, Time, Distance Force, Velocity, Displacement, Acceleration
Mathematical operations Simple arithmetic Vector algebra

Arrow Notation: \(\vec{a}\) or \(\overrightarrow{AB}\)

Component Form (2D):

\[\vec{a} = a_x\hat{i} + a_y\hat{j}\]

or

\[\vec{a} = (a_x, a_y)\]

Component Form (3D):

\[\vec{a} = a_x\hat{i} + a_y\hat{j} + a_z\hat{k}\]

or

\[\vec{a} = (a_x, a_y, a_z)\]

Magnitude:

\[|\vec{a}| = \sqrt{a_x^2 + a_y^2 + a_z^2}\]

Standard Unit Vectors:

  • \(\hat{i} = (1, 0, 0)\) - unit vector along x-axis
  • \(\hat{j} = (0, 1, 0)\) - unit vector along y-axis
  • \(\hat{k} = (0, 0, 1)\) - unit vector along z-axis

1. Zero Vector (\(\vec{0}\)): Magnitude = 0, no specific direction

2. Unit Vector (\(\hat{a}\)): Magnitude = 1

\[\hat{a} = \frac{\vec{a}}{|\vec{a}|}\]

3. Position Vector: Vector from origin to a point P(x, y, z)

\[\vec{r} = x\hat{i} + y\hat{j} + z\hat{k}\]

4. Equal Vectors: Same magnitude and direction

5. Negative Vector (\(-\vec{a}\)): Same magnitude, opposite direction

6. Collinear Vectors: Vectors along the same line (parallel or anti-parallel)

7. Coplanar Vectors: Vectors lying in the same plane

Triangle Law: Place vectors head-to-tail. The resultant is from tail of first to head of last.

Parallelogram Law: The resultant is the diagonal of the parallelogram formed by the two vectors.

Component Method:

\[\vec{R} = \vec{a} + \vec{b} = (a_x + b_x)\hat{i} + (a_y + b_y)\hat{j} + (a_z + b_z)\hat{k}\]

Properties:

  • Commutative: \(\vec{a} + \vec{b} = \vec{b} + \vec{a}\)
  • Associative: \((\vec{a} + \vec{b}) + \vec{c} = \vec{a} + (\vec{b} + \vec{c})\)
  • Additive Identity: \(\vec{a} + \vec{0} = \vec{a}\)

Vector subtraction is defined as:

\[\vec{a} - \vec{b} = \vec{a} + (-\vec{b})\]

Component Method:

\[\vec{a} - \vec{b} = (a_x - b_x)\hat{i} + (a_y - b_y)\hat{j} + (a_z - b_z)\hat{k}\]

Multiplying a vector by a scalar \(k\):

\[k\vec{a} = ka_x\hat{i} + ka_y\hat{j} + ka_z\hat{k}\]

Properties:

  • If \(k > 0\): Same direction, magnitude scaled by \(|k|\)
  • If \(k < 0\): Opposite direction, magnitude scaled by \(|k|\)
  • If \(k = 0\): Results in zero vector

Magnitude: \(|k\vec{a}| = |k||\vec{a}|\)

Definition:

\[\vec{a} \cdot \vec{b} = |\vec{a}||\vec{b}|\cos\theta\]

where \(\theta\) is the angle between the vectors.

Component Form:

\[\vec{a} \cdot \vec{b} = a_xb_x + a_yb_y + a_zb_z\]

Result: Scalar (number)

Key Properties:

  • If \(\vec{a} \cdot \vec{b} = 0\), vectors are perpendicular
  • \(\vec{a} \cdot \vec{a} = |\vec{a}|^2\)
  • \(\hat{i} \cdot \hat{i} = \hat{j} \cdot \hat{j} = \hat{k} \cdot \hat{k} = 1\)
  • \(\hat{i} \cdot \hat{j} = \hat{j} \cdot \hat{k} = \hat{k} \cdot \hat{i} = 0\)

Application: Work done = \(\vec{F} \cdot \vec{d}\)

Magnitude:

\[|\vec{a} \times \vec{b}| = |\vec{a}||\vec{b}|\sin\theta\]

Result: Vector perpendicular to both \(\vec{a}\) and \(\vec{b}\)

Direction: Right-hand rule

Determinant Method:

\[\vec{a} \times \vec{b} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ a_x & a_y & a_z \\ b_x & b_y & b_z \end{vmatrix}\]

Key Properties:

  • \(\vec{a} \times \vec{b} = -\vec{b} \times \vec{a}\) (anti-commutative)
  • \(\vec{a} \times \vec{a} = \vec{0}\)
  • \(\hat{i} \times \hat{j} = \hat{k}\), \(\hat{j} \times \hat{k} = \hat{i}\), \(\hat{k} \times \hat{i} = \hat{j}\)

Applications:

  • Torque: \(\vec{\tau} = \vec{r} \times \vec{F}\)
  • Area of parallelogram: \(|\vec{a} \times \vec{b}|\)

For a vector \(\vec{a} = a_x\hat{i} + a_y\hat{j} + a_z\hat{k}\):

Direction Cosines:

  • \(\cos\alpha = \frac{a_x}{|\vec{a}|}\) (angle with x-axis)
  • \(\cos\beta = \frac{a_y}{|\vec{a}|}\) (angle with y-axis)
  • \(\cos\gamma = \frac{a_z}{|\vec{a}|}\) (angle with z-axis)

Identity:

\[\cos^2\alpha + \cos^2\beta + \cos^2\gamma = 1\]

Solved Examples

Example 1: Vector Components

A vector has magnitude 10 units at 60° above horizontal. Find its components.

Given: Magnitude = 10 units, angle = 60°

Solution:

\[V_x = V\cos\theta = 10\cos60° = 10 \times \frac{1}{2} = 5\]

\[V_y = V\sin\theta = 10\sin60° = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3} \approx 8.66\]

Answer: \(V_x = 5\) units, \(V_y = 5\sqrt{3} \approx 8.66\) units

Example 2: Vector Addition

\(\vec{A} = \langle 4, -3 \rangle\), \(\vec{B} = \langle 1, 6 \rangle\). Find \(\vec{R} = \vec{A} + \vec{B}\) and its magnitude.

Solution:

\[\vec{R} = \vec{A} + \vec{B} = (4 + 1)\hat{i} + (-3 + 6)\hat{j} = 5\hat{i} + 3\hat{j}\]

\[\vec{R} = \langle 5, 3 \rangle\]

Magnitude:

\[|\vec{R}| = \sqrt{5^2 + 3^2} = \sqrt{25 + 9} = \sqrt{34} \approx 5.83\]

Answer: \(\vec{R} = \langle 5, 3 \rangle\), \(|\vec{R}| = \sqrt{34} \approx 5.83\) units

Example 3: Unit Vector

Find the unit vector in the direction of \(\vec{a} = 3\hat{i} + 4\hat{j}\).

Solution:

\[|\vec{a}| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5\]

\[\hat{a} = \frac{\vec{a}}{|\vec{a}|} = \frac{3\hat{i} + 4\hat{j}}{5} = \frac{3}{5}\hat{i} + \frac{4}{5}\hat{j}\]

Answer: \(\hat{a} = 0.6\hat{i} + 0.8\hat{j}\)

Example 4: Dot Product & Angle

Find the angle between \(\vec{u} = \langle 1, 2, 0 \rangle\) and \(\vec{v} = \langle -2, 2, 2 \rangle\).

Solution:

\[\vec{u} \cdot \vec{v} = (1)(-2) + (2)(2) + (0)(2) = -2 + 4 + 0 = 2\]

\[|\vec{u}| = \sqrt{1^2 + 2^2 + 0^2} = \sqrt{5}\]

\[|\vec{v}| = \sqrt{(-2)^2 + 2^2 + 2^2} = \sqrt{12} = 2\sqrt{3}\]

\[\cos\theta = \frac{\vec{u} \cdot \vec{v}}{|\vec{u}||\vec{v}|} = \frac{2}{\sqrt{5} \times 2\sqrt{3}} = \frac{1}{\sqrt{15}}\]

\[\theta = \cos^{-1}\left(\frac{1}{\sqrt{15}}\right) \approx 75°\]

Answer: \(\theta \approx 75°\)

Example 5: Projection

Find the projection of \(\vec{a} = 2\hat{i} + 3\hat{j} + 2\hat{k}\) on \(\vec{b} = \hat{i} + 2\hat{j} + \hat{k}\).

Solution:

\[\vec{a} \cdot \vec{b} = (2)(1) + (3)(2) + (2)(1) = 2 + 6 + 2 = 10\]

\[|\vec{b}| = \sqrt{1^2 + 2^2 + 1^2} = \sqrt{6}\]

Projection:

\[\text{Projection} = \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|} = \frac{10}{\sqrt{6}} = \frac{10\sqrt{6}}{6} = \frac{5\sqrt{6}}{3}\]

Answer: \(\frac{5\sqrt{6}}{3}\) units

Example 6: Cross Product Application

Find the area of the parallelogram with sides \(\vec{a} = 2\hat{i} + 3\hat{j}\) and \(\vec{b} = \hat{i} - 2\hat{j}\).

Solution:

\[\vec{a} \times \vec{b} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 2 & 3 & 0 \\ 1 & -2 & 0 \end{vmatrix}\]

\[= \hat{i}(3 \times 0 - 0 \times (-2)) - \hat{j}(2 \times 0 - 0 \times 1) + \hat{k}(2 \times (-2) - 3 \times 1)\]

\[= \hat{k}(-4 - 3) = -7\hat{k}\]

\[|\vec{a} \times \vec{b}| = |-7\hat{k}| = 7\]

Area of parallelogram: \(|\vec{a} \times \vec{b}| = 7\) square units

Answer: 7 square units

Practice Questions

MCQs

1. Which is a vector quantity?
  • a) Mass
  • b) Speed
  • c) Velocity
  • d) Temperature
Answer: c) Velocity
2. If \(|\vec{A} + \vec{B}| = |\vec{A} - \vec{B}|\), the angle between them is:
  • a) 0°
  • b) 45°
  • c) 90°
  • d) 180°
Answer: c) 90°
3. Dot product of perpendicular vectors equals:
  • a) 1
  • b) 0
  • c) -1
  • d) ∞
Answer: b) 0
4. \(\hat{i} \cdot \hat{j}\) equals:
  • a) 1
  • b) 0
  • c) \(\hat{k}\)
  • d) -1
Answer: b) 0
5. Unit vector has magnitude:
  • a) 0
  • b) 1
  • c) Variable
  • d) Undefined
Answer: b) 1

Short Answer Questions

1. A hiker walks 4 km west, then 3 km north. Find the resultant displacement.
Answer: Resultant displacement = 5 km at 37° north of west (or 53° west of north)
2. Find the unit vector in the direction of \(7\hat{i} - 24\hat{j}\).
Answer: \(\hat{u} = \frac{7}{25}\hat{i} - \frac{24}{25}\hat{j}\)
3. Show that \(\vec{p} = \langle 2, 4, 6 \rangle\) and \(\vec{q} = \langle 1, 2, 3 \rangle\) are collinear.
Answer: \(\vec{p} = 2\vec{q}\), so they are parallel and hence collinear.

Numerical Problems

1. Forces of 5N and 12N act at right angles. Find the resultant magnitude.
Answer: Resultant = \(\sqrt{5^2 + 12^2} = \sqrt{169} = 13\) N
2. Find the angle between \(\vec{a} = 2\hat{i} + 3\hat{j} - \hat{k}\) and \(\vec{b} = \hat{i} - 2\hat{j} + 2\hat{k}\).
Answer: \(\cos\theta = \frac{-2}{\sqrt{14} \times 3} = -\frac{2}{3\sqrt{14}}\), \(\theta \approx 98.2°\)
3. A force of 50N acts at 30° above horizontal. Find its components.
Answer: \(F_x = 50\cos30° = 25\sqrt{3} \approx 43.3\) N, \(F_y = 50\sin30° = 25\) N

MCQs

1. Which is NOT a vector quantity?
  • a) Force
  • b) Momentum
  • c) Energy
  • d) Acceleration
Answer: c) Energy
2. The magnitude of \(\vec{A} + \vec{B}\) is maximum when angle between them is:
  • a) 0°
  • b) 45°
  • c) 90°
  • d) 180°
Answer: a) 0°

Short Answer

1. Define vector and scalar quantities with examples.
Answer: Vector: Has magnitude and direction (e.g., displacement, velocity). Scalar: Has only magnitude (e.g., mass, temperature).

Numericals

1. Two vectors of magnitude 6 and 8 units have an angle of 60° between them. Find their dot product.
Answer: \(\vec{a} \cdot \vec{b} = 6 \times 8 \times \cos60° = 48 \times 0.5 = 24\)
1. Calculate the resultant of 8N horizontal and 6N vertical forces. [4 marks]
Answer: Resultant = \(\sqrt{8^2 + 6^2} = \sqrt{100} = 10\) N at angle \(\theta = \tan^{-1}(6/8) = 36.9°\) above horizontal
2. A vector has magnitude 10 at angle 30°. Find its components. [3 marks]
Answer: \(V_x = 10\cos30° = 5\sqrt{3} \approx 8.66\), \(V_y = 10\sin30° = 5\)
3. Explain the parallelogram law with a diagram. [4 marks]
Answer: When two vectors are represented as adjacent sides of a parallelogram, the diagonal from their common point represents the resultant vector.
A boat can travel 4 m/s in still water. River flows at 3 m/s.
a) Draw a vector diagram [2 marks]
b) Calculate actual velocity [3 marks]
c) What direction should boat point to reach directly opposite? [3 marks]
Answer:
a) Vector diagram shows boat velocity and river velocity
b) Actual velocity = \(\sqrt{4^2 + 3^2} = 5\) m/s at angle \(\theta = \tan^{-1}(3/4) = 36.9°\) downstream
c) Boat should point upstream at angle \(\sin^{-1}(3/4) = 48.6°\) to the perpendicular

Paper 1 Style

Find \(|\vec{a}|\) and unit vector for \(\vec{a} = 3\hat{i} + 4\hat{j}\).
Answer: \(|\vec{a}| = 5\), \(\hat{a} = \frac{3}{5}\hat{i} + \frac{4}{5}\hat{j}\)

Paper 2 Style

Given points A(2,3,0), B(4,-1,2), C(1,0,-3):
a) Find vectors \(\vec{AB}\) and \(\vec{AC}\) [2 marks]
b) Calculate \(\vec{AB} \cdot \vec{AC}\) [2 marks]
c) Find the angle \(\angle BAC\) [3 marks]
Answer:
a) \(\vec{AB} = \langle 2, -4, 2 \rangle\), \(\vec{AC} = \langle -1, -3, -3 \rangle\)
b) \(\vec{AB} \cdot \vec{AC} = 2(-1) + (-4)(-3) + 2(-3) = -2 + 12 - 6 = 4\)
c) \(|\vec{AB}| = \sqrt{24} = 2\sqrt{6}\), \(|\vec{AC}| = \sqrt{19}\), \(\cos\theta = \frac{4}{2\sqrt{6}\sqrt{19}}\), \(\theta \approx 78.5°\)

Quick Revision Tips

Key Points to Remember

  • Vectors have both magnitude and direction; scalars have only magnitude
  • Unit vector has magnitude 1: \(\hat{a} = \frac{\vec{a}}{|\vec{a}|}\)
  • Dot product gives a scalar: \(\vec{a} \cdot \vec{b} = |\vec{a}||\vec{b}|\cos\theta\)
  • Cross product gives a vector perpendicular to both: \(|\vec{a} \times \vec{b}| = |\vec{a}||\vec{b}|\sin\theta\)
  • If \(\vec{a} \cdot \vec{b} = 0\), vectors are perpendicular
  • Component method is often easiest for calculations

Common Mistakes to Avoid

  • Confusing scalar and vector quantities
  • Forgetting to take square root when finding magnitude
  • Mixing up dot product (scalar) and cross product (vector)
  • Not using correct signs in component calculations
  • Forgetting units in final answers

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